Integrand size = 23, antiderivative size = 260 \[ \int \frac {a+b \log \left (c x^n\right )}{x^4 \left (d+e x^2\right )^3} \, dx=-\frac {35 b n}{72 d^3 x^3}+\frac {35 b e n}{8 d^4 x}+\frac {a+b \log \left (c x^n\right )}{4 d x^3 \left (d+e x^2\right )^2}+\frac {7 a-b n+7 b \log \left (c x^n\right )}{8 d^2 x^3 \left (d+e x^2\right )}-\frac {35 a-12 b n+35 b \log \left (c x^n\right )}{24 d^3 x^3}+\frac {e \left (35 a-12 b n+35 b \log \left (c x^n\right )\right )}{8 d^4 x}+\frac {e^{3/2} \arctan \left (\frac {\sqrt {e} x}{\sqrt {d}}\right ) \left (35 a-12 b n+35 b \log \left (c x^n\right )\right )}{8 d^{9/2}}-\frac {35 i b e^{3/2} n \operatorname {PolyLog}\left (2,-\frac {i \sqrt {e} x}{\sqrt {d}}\right )}{16 d^{9/2}}+\frac {35 i b e^{3/2} n \operatorname {PolyLog}\left (2,\frac {i \sqrt {e} x}{\sqrt {d}}\right )}{16 d^{9/2}} \]
-35/72*b*n/d^3/x^3+35/8*b*e*n/d^4/x+1/4*(a+b*ln(c*x^n))/d/x^3/(e*x^2+d)^2+ 1/8*(7*a-b*n+7*b*ln(c*x^n))/d^2/x^3/(e*x^2+d)+1/24*(-35*a+12*b*n-35*b*ln(c *x^n))/d^3/x^3+1/8*e*(35*a-12*b*n+35*b*ln(c*x^n))/d^4/x+1/8*e^(3/2)*arctan (x*e^(1/2)/d^(1/2))*(35*a-12*b*n+35*b*ln(c*x^n))/d^(9/2)-35/16*I*b*e^(3/2) *n*polylog(2,-I*x*e^(1/2)/d^(1/2))/d^(9/2)+35/16*I*b*e^(3/2)*n*polylog(2,I *x*e^(1/2)/d^(1/2))/d^(9/2)
Leaf count is larger than twice the leaf count of optimal. \(584\) vs. \(2(260)=520\).
Time = 1.03 (sec) , antiderivative size = 584, normalized size of antiderivative = 2.25 \[ \int \frac {a+b \log \left (c x^n\right )}{x^4 \left (d+e x^2\right )^3} \, dx=\frac {1}{144} \left (-\frac {16 b n}{d^3 x^3}+\frac {432 b e n}{d^4 x}-\frac {48 \left (a+b \log \left (c x^n\right )\right )}{d^3 x^3}+\frac {432 e \left (a+b \log \left (c x^n\right )\right )}{d^4 x}-\frac {9 e^{3/2} \left (a+b \log \left (c x^n\right )\right )}{(-d)^{7/2} \left (\sqrt {-d}-\sqrt {e} x\right )^2}-\frac {99 e^{3/2} \left (a+b \log \left (c x^n\right )\right )}{d^4 \left (\sqrt {-d}-\sqrt {e} x\right )}+\frac {9 e^{3/2} \left (a+b \log \left (c x^n\right )\right )}{(-d)^{7/2} \left (\sqrt {-d}+\sqrt {e} x\right )^2}+\frac {99 e^{3/2} \left (a+b \log \left (c x^n\right )\right )}{d^4 \left (\sqrt {-d}+\sqrt {e} x\right )}+\frac {99 b e^{3/2} n \left (\log (x)-\log \left (\sqrt {-d}-\sqrt {e} x\right )\right )}{(-d)^{9/2}}-\frac {99 b e^{3/2} n \left (\log (x)-\log \left (\sqrt {-d}+\sqrt {e} x\right )\right )}{(-d)^{9/2}}-\frac {9 b e^{3/2} n \left (\frac {1}{\sqrt {-d} \left (\sqrt {-d}+\sqrt {e} x\right )}-\frac {\log (x)}{d}+\frac {\log \left (\sqrt {-d}+\sqrt {e} x\right )}{d}\right )}{(-d)^{7/2}}-\frac {315 e^{3/2} \left (a+b \log \left (c x^n\right )\right ) \log \left (1+\frac {\sqrt {e} x}{\sqrt {-d}}\right )}{(-d)^{9/2}}+\frac {9 b e^{3/2} n \left (\frac {1}{\sqrt {-d} \left (\sqrt {-d}-\sqrt {e} x\right )}-\frac {\log (x)}{d}+\frac {\log \left ((-d)^{3/2}+d \sqrt {e} x\right )}{d}\right )}{(-d)^{7/2}}+\frac {315 e^{3/2} \left (a+b \log \left (c x^n\right )\right ) \log \left (1+\frac {d \sqrt {e} x}{(-d)^{3/2}}\right )}{(-d)^{9/2}}+\frac {315 b e^{3/2} n \operatorname {PolyLog}\left (2,\frac {\sqrt {e} x}{\sqrt {-d}}\right )}{(-d)^{9/2}}-\frac {315 b e^{3/2} n \operatorname {PolyLog}\left (2,\frac {d \sqrt {e} x}{(-d)^{3/2}}\right )}{(-d)^{9/2}}\right ) \]
((-16*b*n)/(d^3*x^3) + (432*b*e*n)/(d^4*x) - (48*(a + b*Log[c*x^n]))/(d^3* x^3) + (432*e*(a + b*Log[c*x^n]))/(d^4*x) - (9*e^(3/2)*(a + b*Log[c*x^n])) /((-d)^(7/2)*(Sqrt[-d] - Sqrt[e]*x)^2) - (99*e^(3/2)*(a + b*Log[c*x^n]))/( d^4*(Sqrt[-d] - Sqrt[e]*x)) + (9*e^(3/2)*(a + b*Log[c*x^n]))/((-d)^(7/2)*( Sqrt[-d] + Sqrt[e]*x)^2) + (99*e^(3/2)*(a + b*Log[c*x^n]))/(d^4*(Sqrt[-d] + Sqrt[e]*x)) + (99*b*e^(3/2)*n*(Log[x] - Log[Sqrt[-d] - Sqrt[e]*x]))/(-d) ^(9/2) - (99*b*e^(3/2)*n*(Log[x] - Log[Sqrt[-d] + Sqrt[e]*x]))/(-d)^(9/2) - (9*b*e^(3/2)*n*(1/(Sqrt[-d]*(Sqrt[-d] + Sqrt[e]*x)) - Log[x]/d + Log[Sqr t[-d] + Sqrt[e]*x]/d))/(-d)^(7/2) - (315*e^(3/2)*(a + b*Log[c*x^n])*Log[1 + (Sqrt[e]*x)/Sqrt[-d]])/(-d)^(9/2) + (9*b*e^(3/2)*n*(1/(Sqrt[-d]*(Sqrt[-d ] - Sqrt[e]*x)) - Log[x]/d + Log[(-d)^(3/2) + d*Sqrt[e]*x]/d))/(-d)^(7/2) + (315*e^(3/2)*(a + b*Log[c*x^n])*Log[1 + (d*Sqrt[e]*x)/(-d)^(3/2)])/(-d)^ (9/2) + (315*b*e^(3/2)*n*PolyLog[2, (Sqrt[e]*x)/Sqrt[-d]])/(-d)^(9/2) - (3 15*b*e^(3/2)*n*PolyLog[2, (d*Sqrt[e]*x)/(-d)^(3/2)])/(-d)^(9/2))/144
Time = 1.11 (sec) , antiderivative size = 270, normalized size of antiderivative = 1.04, number of steps used = 12, number of rules used = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.522, Rules used = {2785, 25, 2785, 25, 2780, 2741, 2780, 2741, 2761, 27, 5355, 2838}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {a+b \log \left (c x^n\right )}{x^4 \left (d+e x^2\right )^3} \, dx\) |
\(\Big \downarrow \) 2785 |
\(\displaystyle \frac {a+b \log \left (c x^n\right )}{4 d x^3 \left (d+e x^2\right )^2}-\frac {\int -\frac {7 a-b n+7 b \log \left (c x^n\right )}{x^4 \left (e x^2+d\right )^2}dx}{4 d}\) |
\(\Big \downarrow \) 25 |
\(\displaystyle \frac {\int \frac {7 a-b n+7 b \log \left (c x^n\right )}{x^4 \left (e x^2+d\right )^2}dx}{4 d}+\frac {a+b \log \left (c x^n\right )}{4 d x^3 \left (d+e x^2\right )^2}\) |
\(\Big \downarrow \) 2785 |
\(\displaystyle \frac {\frac {7 a+7 b \log \left (c x^n\right )-b n}{2 d x^3 \left (d+e x^2\right )}-\frac {\int -\frac {35 a-12 b n+35 b \log \left (c x^n\right )}{x^4 \left (e x^2+d\right )}dx}{2 d}}{4 d}+\frac {a+b \log \left (c x^n\right )}{4 d x^3 \left (d+e x^2\right )^2}\) |
\(\Big \downarrow \) 25 |
\(\displaystyle \frac {\frac {\int \frac {35 a-12 b n+35 b \log \left (c x^n\right )}{x^4 \left (e x^2+d\right )}dx}{2 d}+\frac {7 a+7 b \log \left (c x^n\right )-b n}{2 d x^3 \left (d+e x^2\right )}}{4 d}+\frac {a+b \log \left (c x^n\right )}{4 d x^3 \left (d+e x^2\right )^2}\) |
\(\Big \downarrow \) 2780 |
\(\displaystyle \frac {\frac {\frac {\int \frac {35 a-12 b n+35 b \log \left (c x^n\right )}{x^4}dx}{d}-\frac {e \int \frac {35 a-12 b n+35 b \log \left (c x^n\right )}{x^2 \left (e x^2+d\right )}dx}{d}}{2 d}+\frac {7 a+7 b \log \left (c x^n\right )-b n}{2 d x^3 \left (d+e x^2\right )}}{4 d}+\frac {a+b \log \left (c x^n\right )}{4 d x^3 \left (d+e x^2\right )^2}\) |
\(\Big \downarrow \) 2741 |
\(\displaystyle \frac {\frac {\frac {-\frac {35 a+35 b \log \left (c x^n\right )-12 b n}{3 x^3}-\frac {35 b n}{9 x^3}}{d}-\frac {e \int \frac {35 a-12 b n+35 b \log \left (c x^n\right )}{x^2 \left (e x^2+d\right )}dx}{d}}{2 d}+\frac {7 a+7 b \log \left (c x^n\right )-b n}{2 d x^3 \left (d+e x^2\right )}}{4 d}+\frac {a+b \log \left (c x^n\right )}{4 d x^3 \left (d+e x^2\right )^2}\) |
\(\Big \downarrow \) 2780 |
\(\displaystyle \frac {\frac {\frac {-\frac {35 a+35 b \log \left (c x^n\right )-12 b n}{3 x^3}-\frac {35 b n}{9 x^3}}{d}-\frac {e \left (\frac {\int \frac {35 a-12 b n+35 b \log \left (c x^n\right )}{x^2}dx}{d}-\frac {e \int \frac {35 a-12 b n+35 b \log \left (c x^n\right )}{e x^2+d}dx}{d}\right )}{d}}{2 d}+\frac {7 a+7 b \log \left (c x^n\right )-b n}{2 d x^3 \left (d+e x^2\right )}}{4 d}+\frac {a+b \log \left (c x^n\right )}{4 d x^3 \left (d+e x^2\right )^2}\) |
\(\Big \downarrow \) 2741 |
\(\displaystyle \frac {\frac {\frac {-\frac {35 a+35 b \log \left (c x^n\right )-12 b n}{3 x^3}-\frac {35 b n}{9 x^3}}{d}-\frac {e \left (\frac {-\frac {35 a+35 b \log \left (c x^n\right )-12 b n}{x}-\frac {35 b n}{x}}{d}-\frac {e \int \frac {35 a-12 b n+35 b \log \left (c x^n\right )}{e x^2+d}dx}{d}\right )}{d}}{2 d}+\frac {7 a+7 b \log \left (c x^n\right )-b n}{2 d x^3 \left (d+e x^2\right )}}{4 d}+\frac {a+b \log \left (c x^n\right )}{4 d x^3 \left (d+e x^2\right )^2}\) |
\(\Big \downarrow \) 2761 |
\(\displaystyle \frac {\frac {\frac {-\frac {35 a+35 b \log \left (c x^n\right )-12 b n}{3 x^3}-\frac {35 b n}{9 x^3}}{d}-\frac {e \left (\frac {-\frac {35 a+35 b \log \left (c x^n\right )-12 b n}{x}-\frac {35 b n}{x}}{d}-\frac {e \left (\frac {\arctan \left (\frac {\sqrt {e} x}{\sqrt {d}}\right ) \left (35 a+35 b \log \left (c x^n\right )-12 b n\right )}{\sqrt {d} \sqrt {e}}-35 b n \int \frac {\arctan \left (\frac {\sqrt {e} x}{\sqrt {d}}\right )}{\sqrt {d} \sqrt {e} x}dx\right )}{d}\right )}{d}}{2 d}+\frac {7 a+7 b \log \left (c x^n\right )-b n}{2 d x^3 \left (d+e x^2\right )}}{4 d}+\frac {a+b \log \left (c x^n\right )}{4 d x^3 \left (d+e x^2\right )^2}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {\frac {\frac {-\frac {35 a+35 b \log \left (c x^n\right )-12 b n}{3 x^3}-\frac {35 b n}{9 x^3}}{d}-\frac {e \left (\frac {-\frac {35 a+35 b \log \left (c x^n\right )-12 b n}{x}-\frac {35 b n}{x}}{d}-\frac {e \left (\frac {\arctan \left (\frac {\sqrt {e} x}{\sqrt {d}}\right ) \left (35 a+35 b \log \left (c x^n\right )-12 b n\right )}{\sqrt {d} \sqrt {e}}-\frac {35 b n \int \frac {\arctan \left (\frac {\sqrt {e} x}{\sqrt {d}}\right )}{x}dx}{\sqrt {d} \sqrt {e}}\right )}{d}\right )}{d}}{2 d}+\frac {7 a+7 b \log \left (c x^n\right )-b n}{2 d x^3 \left (d+e x^2\right )}}{4 d}+\frac {a+b \log \left (c x^n\right )}{4 d x^3 \left (d+e x^2\right )^2}\) |
\(\Big \downarrow \) 5355 |
\(\displaystyle \frac {a+b \log \left (c x^n\right )}{4 d x^3 \left (d+e x^2\right )^2}+\frac {\frac {7 a+7 b \log \left (c x^n\right )-b n}{2 d x^3 \left (d+e x^2\right )}+\frac {\frac {-\frac {35 a+35 b \log \left (c x^n\right )-12 b n}{3 x^3}-\frac {35 b n}{9 x^3}}{d}-\frac {e \left (\frac {-\frac {35 a+35 b \log \left (c x^n\right )-12 b n}{x}-\frac {35 b n}{x}}{d}-\frac {e \left (\frac {\arctan \left (\frac {\sqrt {e} x}{\sqrt {d}}\right ) \left (35 a+35 b \log \left (c x^n\right )-12 b n\right )}{\sqrt {d} \sqrt {e}}-\frac {35 b n \left (\frac {1}{2} i \int \frac {\log \left (1-\frac {i \sqrt {e} x}{\sqrt {d}}\right )}{x}dx-\frac {1}{2} i \int \frac {\log \left (\frac {i \sqrt {e} x}{\sqrt {d}}+1\right )}{x}dx\right )}{\sqrt {d} \sqrt {e}}\right )}{d}\right )}{d}}{2 d}}{4 d}\) |
\(\Big \downarrow \) 2838 |
\(\displaystyle \frac {a+b \log \left (c x^n\right )}{4 d x^3 \left (d+e x^2\right )^2}+\frac {\frac {7 a+7 b \log \left (c x^n\right )-b n}{2 d x^3 \left (d+e x^2\right )}+\frac {\frac {-\frac {35 a+35 b \log \left (c x^n\right )-12 b n}{3 x^3}-\frac {35 b n}{9 x^3}}{d}-\frac {e \left (\frac {-\frac {35 a+35 b \log \left (c x^n\right )-12 b n}{x}-\frac {35 b n}{x}}{d}-\frac {e \left (\frac {\arctan \left (\frac {\sqrt {e} x}{\sqrt {d}}\right ) \left (35 a+35 b \log \left (c x^n\right )-12 b n\right )}{\sqrt {d} \sqrt {e}}-\frac {35 b n \left (\frac {1}{2} i \operatorname {PolyLog}\left (2,-\frac {i \sqrt {e} x}{\sqrt {d}}\right )-\frac {1}{2} i \operatorname {PolyLog}\left (2,\frac {i \sqrt {e} x}{\sqrt {d}}\right )\right )}{\sqrt {d} \sqrt {e}}\right )}{d}\right )}{d}}{2 d}}{4 d}\) |
(a + b*Log[c*x^n])/(4*d*x^3*(d + e*x^2)^2) + ((7*a - b*n + 7*b*Log[c*x^n]) /(2*d*x^3*(d + e*x^2)) + (((-35*b*n)/(9*x^3) - (35*a - 12*b*n + 35*b*Log[c *x^n])/(3*x^3))/d - (e*(((-35*b*n)/x - (35*a - 12*b*n + 35*b*Log[c*x^n])/x )/d - (e*((ArcTan[(Sqrt[e]*x)/Sqrt[d]]*(35*a - 12*b*n + 35*b*Log[c*x^n]))/ (Sqrt[d]*Sqrt[e]) - (35*b*n*((I/2)*PolyLog[2, ((-I)*Sqrt[e]*x)/Sqrt[d]] - (I/2)*PolyLog[2, (I*Sqrt[e]*x)/Sqrt[d]]))/(Sqrt[d]*Sqrt[e])))/d))/d)/(2*d) )/(4*d)
3.3.40.3.1 Defintions of rubi rules used
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))*((d_.)*(x_))^(m_.), x_Symbol] :> Simp[(d*x)^(m + 1)*((a + b*Log[c*x^n])/(d*(m + 1))), x] - Simp[b*n*((d*x)^( m + 1)/(d*(m + 1)^2)), x] /; FreeQ[{a, b, c, d, m, n}, x] && NeQ[m, -1]
Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))/((d_) + (e_.)*(x_)^2), x_Symbol] :> With[{u = IntHide[1/(d + e*x^2), x]}, Simp[u*(a + b*Log[c*x^n]), x] - Si mp[b*n Int[u/x, x], x]] /; FreeQ[{a, b, c, d, e, n}, x]
Int[(((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)*(x_)^(m_.))/((d_) + (e_.)* (x_)^(r_.)), x_Symbol] :> Simp[1/d Int[x^m*(a + b*Log[c*x^n])^p, x], x] - Simp[e/d Int[(x^(m + r)*(a + b*Log[c*x^n])^p)/(d + e*x^r), x], x] /; Fre eQ[{a, b, c, d, e, m, n, r}, x] && IGtQ[p, 0] && IGtQ[r, 0] && ILtQ[m, -1]
Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))*((f_.)*(x_))^(m_.)*((d_) + (e_.)* (x_)^2)^(q_.), x_Symbol] :> Simp[(-(f*x)^(m + 1))*(d + e*x^2)^(q + 1)*((a + b*Log[c*x^n])/(2*d*f*(q + 1))), x] + Simp[1/(2*d*(q + 1)) Int[(f*x)^m*(d + e*x^2)^(q + 1)*(a*(m + 2*q + 3) + b*n + b*(m + 2*q + 3)*Log[c*x^n]), x], x] /; FreeQ[{a, b, c, d, e, f, m, n}, x] && ILtQ[q, -1] && ILtQ[m, 0]
Int[Log[(c_.)*((d_) + (e_.)*(x_)^(n_.))]/(x_), x_Symbol] :> Simp[-PolyLog[2 , (-c)*e*x^n]/n, x] /; FreeQ[{c, d, e, n}, x] && EqQ[c*d, 1]
Int[((a_.) + ArcTan[(c_.)*(x_)]*(b_.))/(x_), x_Symbol] :> Simp[a*Log[x], x] + (Simp[I*(b/2) Int[Log[1 - I*c*x]/x, x], x] - Simp[I*(b/2) Int[Log[1 + I*c*x]/x, x], x]) /; FreeQ[{a, b, c}, x]
Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 1.39 (sec) , antiderivative size = 1029, normalized size of antiderivative = 3.96
1/2*b*n*e^2/d^3*ln(x)/(e*x^2+d)/(-d*e)^(1/2)*ln((-e*x+(-d*e)^(1/2))/(-d*e) ^(1/2))-1/2*b*n*e^2/d^3*ln(x)/(e*x^2+d)/(-d*e)^(1/2)*ln((e*x+(-d*e)^(1/2)) /(-d*e)^(1/2))+3/16*b*n*e^2/d^2*ln(x)/(e*x^2+d)^2/(-d*e)^(1/2)*ln((-e*x+(- d*e)^(1/2))/(-d*e)^(1/2))-3/16*b*n*e^2/d^2*ln(x)/(e*x^2+d)^2/(-d*e)^(1/2)* ln((e*x+(-d*e)^(1/2))/(-d*e)^(1/2))+(-1/2*I*b*Pi*csgn(I*c)*csgn(I*x^n)*csg n(I*c*x^n)+1/2*I*b*Pi*csgn(I*c)*csgn(I*c*x^n)^2+1/2*I*b*Pi*csgn(I*x^n)*csg n(I*c*x^n)^2-1/2*I*b*Pi*csgn(I*c*x^n)^3+b*ln(c)+a)*(1/d^4*e^2*((11/8*e*x^3 +13/8*d*x)/(e*x^2+d)^2+35/8/(d*e)^(1/2)*arctan(x*e/(d*e)^(1/2)))-1/3/d^3/x ^3+3/d^4*e/x)+3*b*e*n/d^4/x+b*n/d^4*e^2*ln(x)*x/(e*x^2+d)+35/8*b*e^2/d^4/( d*e)^(1/2)*arctan(x*e/(d*e)^(1/2))*ln(x^n)+35/16*b*n/d^4*e^2/(-d*e)^(1/2)* dilog((-e*x+(-d*e)^(1/2))/(-d*e)^(1/2))-35/16*b*n/d^4*e^2/(-d*e)^(1/2)*dil og((e*x+(-d*e)^(1/2))/(-d*e)^(1/2))-3/2*b*n*e^2/d^4/(d*e)^(1/2)*arctan(x*e /(d*e)^(1/2))+11/8*b/d^4*e^3/(e*x^2+d)^2*x^3*ln(x^n)+3/8*b*n*e^3/d^3*ln(x) /(e*x^2+d)^2/(-d*e)^(1/2)*ln((-e*x+(-d*e)^(1/2))/(-d*e)^(1/2))*x^2-3/8*b*n *e^3/d^3*ln(x)/(e*x^2+d)^2/(-d*e)^(1/2)*ln((e*x+(-d*e)^(1/2))/(-d*e)^(1/2) )*x^2+1/2*b*n*e^3/d^4*ln(x)/(e*x^2+d)/(-d*e)^(1/2)*ln((-e*x+(-d*e)^(1/2))/ (-d*e)^(1/2))*x^2+3/16*b*n*e^4/d^4*ln(x)/(e*x^2+d)^2/(-d*e)^(1/2)*ln((-e*x +(-d*e)^(1/2))/(-d*e)^(1/2))*x^4-3/16*b*n*e^4/d^4*ln(x)/(e*x^2+d)^2/(-d*e) ^(1/2)*ln((e*x+(-d*e)^(1/2))/(-d*e)^(1/2))*x^4-1/2*b*n*e^3/d^4*ln(x)/(e*x^ 2+d)/(-d*e)^(1/2)*ln((e*x+(-d*e)^(1/2))/(-d*e)^(1/2))*x^2-1/3*b*ln(x^n)...
\[ \int \frac {a+b \log \left (c x^n\right )}{x^4 \left (d+e x^2\right )^3} \, dx=\int { \frac {b \log \left (c x^{n}\right ) + a}{{\left (e x^{2} + d\right )}^{3} x^{4}} \,d x } \]
Timed out. \[ \int \frac {a+b \log \left (c x^n\right )}{x^4 \left (d+e x^2\right )^3} \, dx=\text {Timed out} \]
Exception generated. \[ \int \frac {a+b \log \left (c x^n\right )}{x^4 \left (d+e x^2\right )^3} \, dx=\text {Exception raised: ValueError} \]
Exception raised: ValueError >> Computation failed since Maxima requested additional constraints; using the 'assume' command before evaluation *may* help (example of legal syntax is 'assume(e>0)', see `assume?` for more de tails)Is e
\[ \int \frac {a+b \log \left (c x^n\right )}{x^4 \left (d+e x^2\right )^3} \, dx=\int { \frac {b \log \left (c x^{n}\right ) + a}{{\left (e x^{2} + d\right )}^{3} x^{4}} \,d x } \]
Timed out. \[ \int \frac {a+b \log \left (c x^n\right )}{x^4 \left (d+e x^2\right )^3} \, dx=\int \frac {a+b\,\ln \left (c\,x^n\right )}{x^4\,{\left (e\,x^2+d\right )}^3} \,d x \]